I have adapted this from Stroustrup's "Programming principles and practice using C++" using System Here is my answer(implemented in C#) to those looking for calculator based on grammar based parsing. The logical AND ( &) (logical conjunction) operator for a set of boolean operands will be true if and only if all the operands are true. You only ask for x the first time and ask for y each time the loop repeats. I created JavaScript calculator which takes an operator (+,-, /, ) and 2 numbers. This way, x will contain the result of the previous calculation, allowing you to "chain" it to the next one. Instead of directly printing the result of the calculation, store the result into the x variable, print it out and then ask the user to enter the next y. Sorry for my English, and sorry for my poor c# knowledge, unfortunately, I'm a beginner. Then user must type something for this program to end. I need the result of the first operation to become the first operand and so on. I tried adding doĬonsole.WriteLine("Press ENTER to continue") īut that only makes the program start from the beginning. What I've got not is - two numbers are getting operated and that's all, program stops. Of course, I understand that I must use loop, but can't come up with anyting. The 175-point inspection checklist certified report of 2017 Perodua AXIA G 1.0 used car,Including second hand 2017 Perodua AXIA G 1.
Console calculator multi operator how to#
I don't know, how to make this "chain of calculations". First of all, lets declare a couple of variables and initialize them with an integer and a float, respectively, then type the variable names back in to check that everything is in order: const myInt 5 const myFloat 6. I've successfully added division by zero restriction, but that's about all. Enter the commands listed below into your developer tools JavaScript console. This is what I've got so far: Console.WriteLine("Введите число x") ĭouble x = Convert.ToDouble(Console.ReadLine()) ĭouble y = Convert.ToDouble(Console.ReadLine()) Ĭonsole.WriteLine("// Выберите операцию //") The program must correctly handle errors (division by zero, entering the number instead ofĪrithmetic operators, etc.) and notify the user, without interrupting the work. Which user inputs ("+", "-", "*", "/") and its operands (real numbers), and then calculates,īringing to Screen result of the operation, which is then used in the next operation as theįirst operand (as a result, program will be something like a chain of successive calculations). Revised, now it works with above but still has some trouble with LONG equations.Ī short example is that it solves 2 * 2 * 2 * 2 divided by 5 just fine but if change it soġ0 - 2 * 2 * 2 * 2 divided by 5 I get wrong answer.Develop a console program "Calculator", which reads arithmetic operators in loop iteration,
Console calculator multi operator code#
Here is my code and someone please help me: The reason why it can't solve the other equation is because of how I mapped the strings back into string array.Īfter operations does division first then left to right subtraction then addition Next, based on the Operand result will display. The categories are digits, unary operators ( Sqrt, x², 1/x ), additive operators ( +, - ), and multiplicative operators ( ×, ÷ ). For this C calculator program example, we used the Switch case to check which operand is inserted by the user. Using those two values and operand, it will perform Arithmetic Operations. Second, nothing should happen if Tim hits the same operator key multiple times. May seem more confusing but I couldn't think of any better way. This calculator program in C helps the user to enter the Operator (+, -,, or /) and two values. At this point, you should get a console.log response from every calculator key. After each operation is complete the numbers and operation is replaced with the result of that equation. The reason is that each part, numbers and operations, are split to a string array. It does however solve 10 / 5 + 65 * 2 properly.
My problem is solving a bigger equation such as 10 - 10 / 5 + 3. The it does work with any single operation with +, -, *, and /. The Math method does the single math operations. Im sure there is probably an easier way to do this but what I will need to change/alter is the top method of Matheq. Add several accelerator keys (GTK+) Connect Exp button Exp RPN operation and add Ctrl+Shift+E shortcut Fixes for old KDE and Qt versions New command line. I have the following so far which works fine.
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